`K_(a)` for a weak monobasic acid is `1.0xx10^(-6)`. The `pK_(b)` of its conjugate base base is

If K_a for a weak acid is 10^-5 . pK_b value of its conjugate base is:

The dissociation constant of a weak monobasic acid K_(a) is 1xx 10^(-5) . The pH of 0.1 M of that acid would be

If pK_(a) of a weak acid is 5, then pK_(b) of the conjugate base will

The dissociation constant of a weak monobasic acid K_a is 1 xx 10^-5 . The pH of 0.1 M of that acid would be

K_(h) of salt obtained from strong acid and weak base is 2 xx 10^(-5) . The K_(b) of weak base is

The PK_(a) of a weak acid is 5.85. The concentrations of the acid and its conjugate base are equal at a pH of -

K_a" for "RC-=CH" is "1xx10^-5 . Hence pK_b of conjugate base is…..........

K_a" for "RC-=CH" is "1xx10^-5 . Hence pK_b of conjugate base is…..........

If K_(a)=10^(-5) for a weak acid, then pK_(b) for its conjugate base would be