when two displacements represented by `y_(1) = a sin(omega t)` and `y_(2) = b cos (omega t)` are superimposed the motion is

When two displacement represented by y_(1) = a sin (omega t) and y_(2) = b cos (omega t) are superimposed, the motion is

When two displacement represented by y_(1) = a sin (omega t) and y_(2) = b cos (omega t) are superimposed, the motion is

When two displacement represented by y_1 = a sin t (omegat) and y_2 = b cos t (omegat) are superimposed the motion is

Two wave are represented by equation y_(1) = a sin omega t and y_(2) = a cos omega t the first wave :-

When the waves y_(1) = A sin omega t and y_(2) = A cos omega t are superposed, then resultant amplitude will be

Two waves represented as y_(1) = A_(1) sin omega t and y_(2) = A_(2) cos omega t superpose at a point in space. Find out the amplitude of the resultant wave at that point .

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

The displacements of two intering lightwaves are y_(1) = 4 sin omega t and y_(2) = 3 cos(omega t) . The amplitude of the resultant wave is ( y_(1) and y_(2) are in CGS system)

Two light waves are represented by y_(1)=a sin_(omega)t and y_(2)= a sin(omega t+delta) . The phase of the resultant wave is