Find the angle between the lines `y-sqrt(3)x-5=0`and `sqrt(3)y-x+6=0`.

Explanation

To find the angle between the lines given by the equations \( y - \sqrt{3}x - 5 = 0 \) and \( \sqrt{3}y - x + 6 = 0 \), we can follow these steps:

### Step 1: Convert the equations to slope-intercept form
The slope-intercept form of a line is given by \( y = mx + c \), where \( m \) is the slope.

1. For the first line \( y - \sqrt{3}x - 5 = 0 \):
\[
y = \sqrt{3}x + 5
...