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If alpha, beta and gamma are the zeroes ...

If `alpha`, `beta` and `gamma` are the zeroes of the cubic polynomial `x^3-5x^2+2x-10`, then the value of `(alpha + beta + gamma)(1/alpha + 1/beta +1/ gamma)` is
(1)   `2`     (2)  `0`
(3)   `-1`     (4)  `1`

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