The sum of is `sum_1^16 (n^4/(4n^2 -1))` is

The sum of sum _(n=1)^(16) (n^(4))/(4n^(2) -1) is

The sum of sum _(n=1)^(16) (n^(4))/(4n^(2) -1) is

The sum sum_(n=1)^oo (n/(n^4+4)) is equal to p/q then q-p is ____

The sum sum_(n=1)^oo (n/(n^4+4)) is equal to p/q then q-p is ____

The sum sum_(n=1)^(oo)((n)/(n^(4)+4)) is equal to

Show that the sum of sum_(n=1)^infty n/(n^4+4) equals to 3/8

If sum_(r=1)^(n)r^(4)=F(x), then prove that the value of sum_(n=1)^(n)r(n-r)^(3) is (1)/(4)[n^(3)(n+1)^(2)-4F(x)]

The value of sum_(n=1)^(oo)(4n-2)/(3^(n))

Let a_n=16 ,4,1, be a geometric sequence. Define P_n as the product of the first n terms. Then the value of 1/4sum_(n=1)^oo P_n^(1/n) is _________.