`inttan^(- 1)sqrt((1-sinx)/(1+sinx))dx ,-pi/2

int tan^(-1)sqrt((1-sinx)/(1+sinx))dx.

Evaluate the following : inttan^-1 sqrt((1-sinx)/(1+sinx))dx .

Differentiate tan^(-1){sqrt((1+sinx)/(1-sinx))}, -pi/2

Differentiate tan^(-1){sqrt((1+sinx)/(1-sinx))},\ -pi/2

Differentiate the following functions with respect to x : tan^(-1){sqrt((1+sinx)/(1-sinx))},-pi/2ltxltpi/ 2

If y=tan^(-1)sqrt(((1+sinx)/(1-sinx))),(pi)/(2)ltxltpi, then (dy)/(dx) equals to

Evaluate inttan^(-1)((1-cosx)/(sinx))dx

d/dx[sqrt((1+sinx)/(1-sinx))]

sqrt((1+sinx)/(1-sinx))=tan(pi/4+x/2)

If y= tan^(-1)sqrt((1-sinx)/(1+sinx)) , then the value of (dy)/(dx) at x= (pi)/6 is.