A body cools in a surrounding of constant temperature `30^@C` Its heat capacity is `2 J//^(@)C`. Initial temeprature of cooling is valid. The body cools to `38^@C` in 10 min
When the body temperature has reached `38^@C`, it is heated again so that it reches `40^@C` in 10 min. The heat required from a heater by the body is

A body cools in a surrounding of constant temperature 30^@C Its heat capacity is 2 J//^(@)C . Initial temperature of cooling is valid. The body of mass 1 kg cools to 38^@C in 10 min When the body temperature has reached 38^@C , it is heated again so that it reaches 40^@C in 10 min. The heat required from a heater by the body is

A body cools in a surrounding of constant temperature 30^@C Its heat capacity is 2 J//^(@)C . Initial temeprature of cooling is valid. The body cools to 38^@C in 10 min In further 10 min it will cools from 38^@C to _____

A body cools in a surrounding of constant temperature 30^(@)C . Its heat capacity is 2J//^(@)C . Initial temperature of the body is 40^(@)C . Assume Newton's law of cooling is valid. The body cools to 36^(@)C in 10 minutes. When the body temperature has reached 36^(@)C . it is heated again so that it reaches to 40^(@)C in 10 minutes. Assume that the rate of loss of heat at 38^(@)C is the average rate of loss for the given time . The total heat required from a heater by the body is :

A body cools in a surrounding of constant temperature 30^(@)C . Its heat capacity is 2J//^(@)C . Initial temperature of the body is 40^(@)C . Assume Newton's law of cooling is valid. The body cools to 36^(@)C in 10 minutes. When the body temperature has reached 36^(@)C . it is heated again so that it reaches to 40^(@)C in 10 minutes. Assume that the rate of loss of heat at 38^(@)C is the average rate of loss for the given time . The total heat required from a heater by the body is :

A body cools in a surrounding of constant temperature 30^@C Its heat capacity is 2 J//^@C . Initial temeprature of cooling is valid. The body cools to 38^@C in 10 min The temperature of the body In .^@C denoted by theta . The veriation of theta versus time t is best denoted as

A body cools in a surrounding of constant temperature 30^@C Its heat capacity is 2 J//^@C . Initial temeprature of cooling is valid. The body cools to 38^@C in 10 min The temperature of the body In .^@C denoted by theta . The veriation of theta versus time t is best denoted as

A body cools in a surrounding of constant temperature 30^@C Its heat capacity is 2 J//^@C . Initial temeprature of cooling is valid. The body cools to 38^@C in 10 min The temperature of the body In .^@C denoted by theta . The veriation of theta versus time t is best denoted as

A body having mass 2 Kg cools in a surrounding of constant temperature 30^(@)C . Its heat capacity is 2J//^(@)C . Initial temperature of the body is 40^(@)C . Assume Newton's law of cooling is valid. The body cools to 36^(@)C in 10 minutes. When the body temperature has reached 36^(@)C . it is heated again so that it reaches to 40^(@)C in 10 minutes. Assume that the rate of loss of heat at 38^(@)C is the average rate of loss for the given time . The total heat required from a heater by the body is :

A body cools in a surrounding of constant temperature 30^@C Its heat capacity is 2 J//^(@)C . Initial temeprature of cooling is 40^@C and assuming newtons law of cooling is valid. The body cools to 38^@C in 10 min In further 10 min it will cools from 38^@C to _____

A body cools in a surrounding of constant temperature 30^(@)C . Its heat capacity is 2J//^(@)C . Initial temperature of the body is 40^(@)C . Assume Newton's law of cooling is valid. The body cools to 36^(@)C in 10 minutes. In further 10 minutes it will cool from 36^(@)C to :