The side BC of a `DeltaABC` is bisected at D. O is any point on AD. BO and CO are produced to meet AC and AB at E & F respectively. AD is produced to C1 so that D is the mid-point of OC1. Prove that FE||BC.

The side BC of a DeltaABC is bisected at D. O is any point on AD, BO and CO are produced to meet AC and AB at E and F respectively and AD is produced to G so that D is the midpoint of OG. Prove that FE|| BC

The side BC of a triangle ABC is bisected at D; O is any point in AD. BO and CO produced meet AC and AB in E and F respectively and AD is produced to X so that D is the mid-point of OX. Prove that AO:AX=AF:AB and show that FE||BC.

The side B C of a triangle A B C is bisected at D ; O is any point in A D. BO and CO produced meet AC and AB in E and F respectively and A D is produced to X so that D is the mid-point of O X . Prove that A O : A X=A F : A B and show that FE||BC .

The side BC of a triangle ABC is bisected at D;o is any point in AD,BO and CO produced meet AC and AB in E and F respectively and AD is produced to X so that D is the mid-point of OX. Prove that AO:AX=AF:AB and show that FE|BC.

In the given figure, side BC of Delta ABC is bisected at D and O is any point AD.BO and CO produced meet AC and AB at E and F respectively, and AD is respectively, and AD is produced to X so that D is the midpoint of OX. Prove that AO:AX=AF:AB and show that EF||BC .

In the adjoining figure, D is the mid-point of BC. If BM and CN are perpendiculars from B and C respectively on AD and AD produced, then prove that BM = CN.

In the adjoining figure, D is the mid-point of BC. If BM and CN are perpendiculars from B and C respectively on AD and AD produced, then prove that BM = CN.

In triangle ABC, D and E are mid-points of sides AB and BC respectively. Also, F is a point in side AC so that DF is parallel to BC (i) Prove that DBEF is a parallelogram.

D is the mid-point of side BC of a A ABC. AD is bisected at the point E and BE produced cuts AC at the point X. Prove that BE : EX = 3:1

In a triangle ABC,D is the mid - point of BC, AD is produced upto E so that DE = AD. Prove that : AB=EC