In an experiment, 50 mL of 0.1 M solution off a metallic salt `M(NO_(3))` reacted exactly with 25 mL of 0.1 M solution of `NaSO_(3)` in the reaction `SO_(3)^(2-)` is oxidized to `SO_(4)^(2-)`. If in the original salt oxidation number fo the metal was 3, what would be the new oxidation number of metal?

In an experiment, 50 ml of 0.1 M solution of a salt reacted with 25 ml of 0.1 M solution of sodium sulphite. The half equation for the oxidation of sulphite ion : SO_(3(aq))H_2OrarrSO_(4(aq))^(2-)+2H_((aq))^+ If the oxidation number of the metal in the salt was 3, what would be the new oxidation number of the metal ?

50 mL of 0.1 M solution of a salt reacted with 25 mL of 0.1 M solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is: SO_(3)^(2-)(aq)+H_(2)O(l) rarr (aq)+2H^(+)(aq)+2e^(-) If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal:

50 mL of 0.1 M solution of a salt reacted with 25 mL of 0.1 M solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is: SO_(3)^(2-)(aq)+H_(2)O(l) rarr (aq)+2H^(+)(aq)+2e^(-) If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal:

50 mL of 0.1M solution of a salt reacted with 25 mL of 0.1M solution of sodium sulphite. The half reaction for the oxidation of sulphate ion is: SO_(3(aq.))^(2-)+H_(2)O_((l))rarrSO_(4(aq.))^(2-)+2H_(+(aq.))+2e If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal?

In an experiment 50ml of 0.1(M) solution of a salt is reacted with 25ml of 0.1(M) solution of sodium sulphite. The half equation for the oxidation of sulphite ion is SO_(3)^(2-)(aq)+H_(2)O rarr SO_(4)^(2-)(aq)+2H^(+)(aq)+2e^(-) If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal?

25 mL of 0.1 M solution of metallic salt (A) oxidised 25 mL of 0.1 M sodium sulphite to sodium sulphate. If oxidation number of the metal in the salt (A) is 3, then new oxidation number of the metal is __________

20 ml of 0.1 M solution of metal ion reacted with 20 ml to 0.1 M SO_(2) solution . SO_(2) reacted according to the equation SO_(2) + 2H_(2)O rarr SO_(4)^(2-) + 4H^(+) + 2e^(-) . If the oxidation no. of metal ion was + 3 , the new oxidation number of the metal would be :

15.0 mL of 0.05 M SeO_2 reacts with 30.6 mL of 0.1 M CrSO_4 solution . If during the reaction CrSO_4 gets oxidised to Cr_2(SO_4)_3 to what oxidation state does selenium get converted ?

25ml of a 0.1(M) solution of a stable cation of transition metal z reacts exactly with 25 ml of 0.04(M) acidified KMnO_(4) solution. Which of the following is most likely to represent the change in oxidation state of Z correctly?