let `2..^(20)C_(0)+5.^(20)C_(1)+8.^(20)C_(2)+?.+62.^(20)C_(20)`. Then sum of this series is (A) `16.2^(22)` (B) `8.2^(21)` (C) `8.2^(21)` (D) `16.2^(21)`

1.^(20)C_(1)-2.^(20)C_(2)+3.^(20)C_(3)-...-20.^(20)C_(20)

The sum ""^(20)C_(0)+""^(20)C_(1)+""^(20)C_(2)+……+""^(20)C_(10) is equal to :

The sum ""^(20)C_(0)+""^(20)C_(1)+""^(20)C_(2)+……+""^(20)C_(10) is equal to :

Evaluate: .^(20)C_(5)+^(20)C_(4)+^(21)C_(4)+^(22)C_(4)

Evaluate: .^(20)C_(5)+^(20)C_(4)+^(21)C_(4)+^(22)C_(4)

The value of (.^(21)C_(1) - .^(10)C_(1)) + (.^(21)C_(2) - .^(10)C_(2)) + (.^(21)C_(3) - .^(10)C_(3)) + (.^(21)C_(4) - .^(10)C_(4)) + … + (.^(21)C_(10) - .^(10)C_(10)) is (A) 2^(21) - 2^(11) (B) 2^(21) - 2^(10) (C) 2^(20) - 2^(9) (D) 2^(20) - 2^(10)

The sum of the series .^(20)C_(0)-.^(20)C_(1)+ .^(20)C_(2)-.^(20)C_(3)+...-.+ .^(20)C_(10) is -

The sum of the series .^(20)C_(0)-.^(20)C_(1)+ .^(20)C_(2)-.^(20)C_(3)+...-.+ .^(20)C_(10) is -

The sum of the series sum_(r=0)^(10) .^(20)C_(r) , is 2^(19)+{(.^(20)C_(10))/2} .

The sum of series .^(20)C_0-^(20)C_1+^(20)C_2-^(20)C_3+....+^(20)C _10 is