`tan (alpha + beta)=1/2 , tan (alpha-beta)=1/3`, then find the value of `tan2 alpha`

tan (alpha + beta) =1/2, tan(alpha - beta) = 1/3 "then the value of" tan^(2) alpha is-

If sin(alpha+beta)=1 and sin(alpha-beta)=1/2 , where 0lt=alpha, betalt= pi/2 , then find the values of tan(alpha+2beta) and tan(2alpha+beta) .

If 2tan alpha=3tan beta then tan(alpha-beta)=

If cos(alpha+beta)+sin(alpha-beta)=0 and tan beta ne1 , then find the value of tan alpha .

If cos(alpha+beta)+sin(alpha-beta)=0 and tan beta ne1 , then find the value of tan alpha .

If tan alpha = sqrt(3) and tan beta = (1)/(sqrt(3)) , then find the value of cot (alpha + beta) .

If tan alpha = 7/5, tan beta=5/7 " then find the values of " tan (alpha + beta) " and " cot (alpha - beta)

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =

If sin (alpha+beta)=1, sin (alpha-beta)=1/2 , then tan (alpha+ 2beta). tan (2 alpha+beta) is equal to :