Find the points of intersection of the line `(x-2)/(-3)=(y-1)/2=(z-3)/2` and the plane `2x+y-z=3`.

Find the point of intersection of the line (x-1)/(2)=(2-y)/(3)=(z+3)/(4) and the plane 2x + 4y - z = 1. Also find the angle between them.

Find the points of intersection of the line (x-1)/1=(y+2)/ 3 =(z-1)/(-1) and the plane 2x+y+z=9.

The point of intersection of the line (x)/(1)=(y-1)/(2)=(z+2)/(3) and the plane 2x+3y+z=0 is

The point of intersection of the line (x)/(1)=(y-1)/(2)=(z+2)/(3) and the plane 2x+3y+z=0 is

Find the point of intersection of the line (x-2)/3 = (y + 1)/4 = (z - 2)/12 and the plane x - y + z = 5.

Distance of the origin from the point of intersection of the line (x)/(2)=(y-2)/(3)=(z-3)/(4) and the plane 2x+y-z=2 is

Find the equation of the line passing through the point P(4,6,2) and the point of intersection of the line (x-1)/(3)=(y)/(2)=(z+1)/(7) and the plane x+y-z=8^(3)

The point of intersection of the line (x-1)/3=(y+2)/4=(z-3)/-2 and the plane 2x-y+3z-1=0 , is

The point of intersection of the line (x-1)/3=(y+2)/4=(z-3)/-2 and the plane 2x-y+3z-1=0 , is