Time period `(T)` and amplitude `(A)` are same for two particle which undergoes `SHM` along the same line At same particle instant are particle is it phase`(3pi)/(2)`and ather From the phase zero while moving in the same direction Fimd the time at which they will cross each other

Time period (T) and amplitude (A) are same for two particle which undergoes SHM along the same line. At one particular instant one particle is at phase (3pi)/(2) and the other is at zero,while moving in the same direction. Find the time at which they will cross each other

Two particle of same time period (T) and amplitude undergo SHM along the same line with initial and phase of pi//6 . If they start at the same point along the opposite directions. Find the time other which they will meet again for the first time

Two particles execute S.H.M. along the same line at the same frequency. They move in opposite direction at the mean position. The phase difference will be :

Two particles are in SHM with same amplitude A and same regualr frequency omega . At time t=0, one is at x = +A/2 and the other is at x=-A/2 . Both are moving in the same direction.

Two particles are in SHM with same amplitude A and same regualr frequency omega . At time t=0, one is at x = +A/2 and the other is at x=-A/2 . Both are moving in the same direction.

Two particle undergoes SHM along parallel line with the same time period (T) and equal amplitude At a particular instant , one particle is at its extereme position while the other is at its mean position .They move in the same direction .They will cross each other after a further time