Two identical tubes `A` and `B` are kept in air and water respetively as shown. If the fundamental frequency of `A` is `f_(0)`, then thr fundamental frequency of `B` is

The second overtone of an open pipe A and a closed pipe B have the same frequencies at a given temperature. Both pipes contain air. The raito of fundamental frequency of A to the fundamental frequency of B is:

The length , radius , tension and density of string A are twice the same parameters of string B . Find the ratio of fundamental frequency of B to the fundamental frequency of A .

The length , radius , tension and density of string A are twice the same parameters of string B . Find the ratio of fundamental frequency of B to the fundamental frequency of A .

The second overtone of an open pipe A and closed pipe B have the same frequencies at a given temperature. Both pipes contain air. The ratio of fundamental frequency of a to the fundamental frequency of B is

The second overtone of an open pipe A and a closed pipe B have the same frequencies at a given temperature. Both pipes contain air. The ratio of fundamental frequency of A to the fundamental frequency of B is: (A) 3:5 (B) 5:3 (C) 5:6 (D) 6:5

When an open pipe is vertically dipped in water 8cm is inside the water, then the fundamental frequency of air column is 400Hz. If it is 6cm inside the water then fundamental frequency of the air column is 300Hz. Then the length of the tube will be

A tube, open at only one end, is cut into two shorter (non equal) lengths. The piece that is open at both ends has a fundamental frequency of 425 Hz, while the piece open only at one end has a fundamental frequency of 675 Hz. What is the fundamental frequency of the original tube?