`|x-2|<=|x+4|`

Solve the following (i) | x-2 | = (x-2) (ii) |x+3 |=-x-3 (iii) |x^2-x|=x^2-x (iv) |x^2-x-2|=2 +x-x^2

If |x^2-2x+2|-|2x^2-5x+2|=|x^2-3x| then the set of values of x is

If |x^2-2x+2|-|2x^2-5x+2|=|x^2-3x| then the set of values of x is

If |x^2-2x+2|-|2x^2-5x+2|=|x^2-3x| then the set of values of x is

If |x^2-2x+2|-|2x^2-5x+2|=|x^2-3x| then the set of values of x is

f(x)={(a|x^(2)-x-2|)/(2+x-x^(2)),x<2 and b,x=2 and (x-[x])/(x-2),x is continuous at x=2 and [] is GLF.then valueof a and b are

(x+1) is a factor of the polynomial a. x^3-2x^2+x+2 b. x^3+2x^2-x-2 c. x^3+2x^2+x-2 d. x^3+2x^2-x+2

Solve (x-2)/(x+2)+(x+2)/(x-2)=4