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int0^(pi//2)(cosx)/((2+sinx)(1+sinx))dx ...

`int_0^(pi//2)(cosx)/((2+sinx)(1+sinx))dx` equals (a)`log(2/3)` (b) `log(3/2)` (c) `log(3/4)` (d) `log(4/3)`

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int_(0)^( pi/2)(cos x)/((2+sin x)(1+sin x))dx equals (a)log((2)/(3))(b)log((3)/(2))(c)log((3)/(4))(d)log((4)/(3))

int_(0)^(pi//2)log(sinx)dx=

int_(0)^(pi//2)(sinx-cosx)log(sinx+cosx)dx=0

int_(0)^(pi//2)(sinx-cosx)log(sinx+cosx)dx=0

int_(-pi/4)^(pi/4) log((2 - sinx)/(2 + sinx)) dx=

int_(0)^((pi)/(2))(cosxdx)/((1+sinx)(2+sinx)(3+sinx))=(1)/(2)log.(32)/(27)

Evaluate: int_0^(pi/2)log((4+3sinx)/(4+3cosx))dx

Evaluate: int_0^(pi/2)log((4+3sinx)/(4+3cosx))dx

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show that int_(0)^(pi//2)(sinx-cosx)log(sinx+cosx)dx=0