If lim(x->0)[1+x1n(1+b^2)]^(1/x)=2b...

If `lim_(x->0)[1+x1n(1+b^2)]^(1/x)=2bsin^2theta,b >0`,where `theta in (-pi,pi],` then the value of `theta` is (a)`+-pi/4` (b) `+-pi/3` (c) `+-pi/6` (d) `+-pi/2`

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