A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. Surface tension of mercury `=0.465Jm^-2`

Eight droplets of mercury each of radius 1 mm coalesces into a single drop. Find the change in the surface energy. Surface tension of mercury is 0.465 J//m^2

A drop of water 1mm radius is split into 64tiny drops. Find the increase in surface energy.[ S=72xx10^-3 Nm^-1 ]

Eight droplets of water, each of radius 0.2 mm, coalesce into a single drop . Find the change in total surface energy. (Surface tension of water = 0.072 N/m)

Twenty seven droplets of water, each of radius 0.1 mm coalesce into a single drop. Find the change in surface energy. Surface tension of water is 0.072 N//m .

Twenty seven droplets of water, each of radius 0.1 mm coalesce into a single drop. Find the change in surface energy. Surface tension of water is 0.072 N/m.

A mecury drop of radius 1 cm is sprayed into 10^(5) droplets of equal size. Calculate the increase in surface energy if surface tension of mercury is 35xx10^(-3)N//m .

A mecury drop of radius 1 cm is sprayed into 10^(5) droplets of equal size. Calculate the increase in surface energy if surface tension of mercury is 35xx10^(-3)N//m .

Twenty seven droplets of water , each of radius 1.1 mm coalesce into a single drop .Find the change in surface energy. Surface tension of water is 0.072 N/m.

A drop of liquid of diameter 2.8 mm split into 125 identical drops .The change in energy is …..(Surface tension T=75dyne/cm)