Find the result of mixing 0.5 kg ince at `0^@C` with 2 kg water at `30^@C`. Given that latent heat of ice is `L=3.36xx10^5 J//kg` and specific heat of water is `4200 J//kg//K`.

Find the result of mixing 0.5 kg ice at 0^@C with 2 kg water at 30^@C . Given that latent heat of ice is L=3.36xx10^5 J//kg and specific heat of water is 4200 J//kg//K .

Find the result of mixing 1kg of ice at 0^(@)C with 1.5kg of water at 45^(@)C . (Specific latent heat of fusioin of ice =336xx10^(3)Jkg^(-1) )

Find the amount of heat required to convert 10 kg ice at -10^(@)C to water at 50^(@)C . Given specific heat of ice 2100Jkg^(-1)K^(-1) , specific heat of water 4200Jkg^(-1)K^(-1) and latent heat of ice 3.36xx10^5Jkg^(-1)

Find the final temeprature and composition of the mixture of 1 kg of ice at -10^(@)C and 4.4 kg of water at 30^(@)C . Given that specific heat of water is 4200J//kg^(@)C and that of ice is 2100J//kg^(@)C and latent heat of fusion of ice is 3.36xx10^(5) J/kg

What will be the result of mixing 2kg of cooper at 100^(@)C with 0.75 kg of ice at 0^(@)C (Specific heat capacity of cooper =378J kg^(-1)K^(-1) specific heat capacity of water =4200 J kg^(-1)K^(-1) and specific latent heat of fusion of ice =336xx10^(3)Jkg^(-1) )

Find the final temperature and composition of the mixtue of 1 kg of ice at 0^(@)C and 1.5 kg of water at 45^(@)C . Given that specific heat of water is 4200 J/kg and latent heat of fusion of ice is 3.36xx10^(5)J//kg

Find the quantity of heat required to convert 40 g of ice at -20^(@) C into water at 20^(@) C. Given L_(ice) = 0.336 xx 10^(6) J/kg. Specific heat of ice = 2100 J/kg-K Specific heat of water = 4200 J/kg-K

Find the quantity of heat required to convert 40 g of ice at -20^(@) C into water at 20^(@) C. Given L_(ice) = 0.336 xx 10^(6) J/kg. Specific heat of ice = 2100 J/kg-K Specific heat of water = 4200 J/kg-K

Find the quantity of heat required to convert 40 g of ice at -20^(@) C into water at 20^(@) C. Given L_(ice) = 0.336 xx 10^(6) J/kg. Specific heat of ice = 2100 J/kg-K Specific heat of water = 4200 J/kg-K

How should 1 kg of water at 50^(@)C be divided in two parts such that if one part is turned into ice at 0^(@)C . It would release sufficient amount of heat to vapourize the other part. Given that latent heat of fusion of ice is 3.36xx10^(5) J//Kg . Latent heat of vapurization of water is 22.5xx10^(5) J//kg and specific heat of water is 4200 J//kg K .