Suppose, the daughter nucleus in a nuclear decay is itself radioactive. Let `lambda_p and lambda_d` be the decay constants of the parent and the daughter nuclei. Also, let `N_p and N_d` be the number of parent and daughter nuclei at time `t`. Find the condition for which the number of daughter nuclei becomes constant.

Let lambda_(p) and lambda_(d) be the decay constants of the parent and the daughter nuclei.If N_(P) and N_(d) be the number of parent and daughter nuclei at time t the condition that the daughter nuclei become constant is : 1) lambda_(p)N_(p)=lambda_(d)N_(d) 2) lambda_(p)N_(d)=lambda_(d)N_(p) 3) lambda_(p)lambda_(d)=N_(p)N_(d) 4) None of these

A radioactive nucleus emits a beta particle. The parent and daughter nuclei are:

A radioactive nucleus emits beta particle. The parent and daughter nuclei are

In an alpha decay, the daughter nucleus produced is itself unstable and undergoes further decay. If the number of parent and daughter nuclei at time t are Nl_p and N_d respectively and their decay constant are lambda_p and lambda_d respectively. What condition needs to be satisfied in order for Nd to remain constant ?

Decay constant of two radioactive samples is lambda and 3lambda respectively. At t = 0 they have equal number of active nuclei. Calculate t , when will be the ratio of active nuclei becomes e : 1 .

A stable nuclei C is formed from two radioactive nuclei A and B with decay constant of lambda_1 and lambda_2 respectively. Initially, the number of nuclei of A is N_0 and that of B is zero. Nuclei B are produced at a constant rate of P. Find the number of the nuclei of C after time t.

A stable nuclei C is formed from two radioactive nuclei A and B with decay constant of lambda_1 and lambda_2 respectively. Initially, the number of nuclei of A is N_0 and that of B is zero. Nuclei B are produced at a constant rate of P. Find the number of the nuclei of C after time t.