`f(x)={ 5 ; xle1, a+bx; 1lt x lt 3, b+5x; 3le x lt5, 30 xge5` then

f(x)={:{(5, x le 1) ,(a+bx,1 lt x lt 3),(b+5x,3 le x lt 5),(30,xge5):} then (a) f(x) is discontiuous AA a in R, b in R (b) f(x) is discontiuous if a=0 & b=5 (c) f(x) is discontiuous if a=5 & b=0 (d) f(x) is discontiuous if a=-5 & b=10

f(x)={:{(5, x le 1) ,(a+bx,1 lt x lt 3),(b+5x,3 le x lt 5),(30,xge5):} then (a) f(x) is discontiuous AA a in R, b in R (b) f(x) is discontiuous if a=0 & b=5 (c) f(x) is discontiuous if a=5 & b=0 (d) f(x) is discontiuous if a=-5 & b=10

Let f:R to R be a function defined as f(x)={{:(5,"if" x le 1),(a+bx , "if" 1 lt x lt 3),(b+5x , "if" 3 le x lt 5),(30 , "if" x ge 5):} then f is

If f(x)={:{(3", if " 0 le x le 1),(4", if " 1 lt x lt 3),(5", if " 3 le x le 10):} , then

Let f:RtoR be a function defined as f(x)={(5,"if", xle1),(a+bx,"if", 1ltxlt3),(b+5x,"if",3lexlt5),(30,"if",xge5):} Then f is :

f(x) = (2x^(2) + 3)/(5) , for oo lt x le 1 = 6 -5x , for 1 lt x lt 3 = x-3 , for 3 le x lt 8 , then

f(x) = (2x^(2) + 3)/(5), for oo lt x le 1 = 6 -5x, for 1 lt x lt 3 = x-3, for 3 le x lt 8, then

If |x - 2| lt 3 then -1 lt x lt 5 .

Let f:RtoR be a function defined as f(x)={(5,"if", xle1),(a+bx,"if", 1ltxlt3),(b+5x,"if",3lexlt3),(30,"if",xge5):} Then f is :