A compound `X` react with `Na_(2)O_(2)` and forms `Y`, `Y` is reacted with nitric acid and then treated with ammonium molybdate to give yellow ppt.

Ammonia reacts with nitric acid to form

For the detection of phosphorus, the organic compound after fustion with Na_(2)O_(2) is extracted with water, boiled with HNO_(3) and then ammonium molybdate is added to it. A yellow pppt. Is obtained which is due to the formation of

An organic compound 'A' is oxidized with Na_(2)O_(2) followed by boiling with HNO_(3) . The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate. Based on above observation,the element present in the given compound is :

An organic compound 'A' is oxidized with Na_(2)O_(2) followed by boiling with HNO_(3) . The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate. Based on above observation,the element present in the given compound is :

Concentrated nitric acid reacts with iodine to give:

Phosphorus pentoxide reacts with nitric acid to form.

White phosphorus when reacts with nitric acid gives