Home
Class 12
PHYSICS
An isotope .(92)U^(238) decays successiv...

An isotope `._(92)U^(238)` decays successively to form `._(90)Th^(234),._(91)Pa^(234),._(90)Th^(234),._(90)Th^(230)` and `._(88)Ra^(226)`. What are the radiations emitted in these five steps?

Promotional Banner

Similar Questions

Explore conceptually related problems

An isotope _(92)U^(238) decays successively to form _(90)Th^(234),_(91)Pa^(234),_(92)U^(234),_(90)Th^(230) and _(88)Ra^(226) .What are the radiation emitted in these five steps?

The isotope ._92U^238 decays successively to form ._90Th^234 , ._91Pa^234 , ._92U^234 , ._90Th^230 and ._88Ra^226 . What are the radiations emitted in these five steps?

Part of uranium decay series is shown ._(92)U^(234) to ._(90)Th^(234) to ._(91) Pa^(234) to ._(90)Th^(230) to ._(88)Ra^(226) How many parts of isotopes are there in the above series

Part of uranium decay series is shown ._(92)U^(234) to ._(90)Th^(234) to ._(91) Pa^(234) to ._(90)Th^(230) to ._(88)Ra^(226) How many parts of isotopes are there in the above series

Complete the reaction : ""_90Th^(234) to ""_91Pa^(234) +?