A particle is executing simple harmonic motion with an amplitude A and time period T. The displacement of the particles after 2T period from its initial position is

A particle is excuting simple harmonic motion with an amplitude A and time period T. The dispolacement of the particle after 2 T period from its intial position is,

For a particle executing simple harmonic motion, the amplitude is A and time period is T. The maximum speed will be

A particle executing simple harmonic motion with an amplitude A. The distance travelled by the particle in one time period is

A particle executes simple harmonic motion. The amplitude of vibration of particle is 2 cm. The displacement of particle in one time period is

A particle executing simple harmonic motion with an amplitude 5 cm and a time period 0.2 s. the velocity and acceleration of the particle when the displacement is 5 cm is

A particle executing simple harmonic motion with an amplitude 5 cm and a time period 0.2 s. the velocity and acceleration of the particle when the displacement is 5 cm is

A particle is executing simple harmonic motion with an amplitude of 10 cm and time period of 4s. Calculate its displacement, velocity and acceleration after 1/2 seconds, starting from the mean position.

A particle executing simple harmonic motion has amplitude of 1 m and time period 2 s . At t = 0 , net force on the particle is zero. Find the equation of displacement of the particle.