A particle of mass `m` is allowed to oscillate near the minimum of a vertical parabolic path having the equaiton `x^(2) =4ay`. The angular frequency of small oscillation is given by

A point mass m is displaced slightly from point O and released. It is constrained to move along parabolic path having equation x^(2)=ky then its angular frequency of oscillation is :

A point mass m is displaced slightly from point O and released. It is constrained to move along parabolic path having equation x^(2)=ky then its angular frequency of oscillation is :

A particle of mass m moves in a one dimensional potential energy U(x)=-ax^2+bx^4 , where a and b are positive constant. The angular frequency of small oscillation about the minima of the potential energy is equal to

A particle of mass m moves in a one dimensional potential energy U(x)=-ax^2+bx^4 , where a and b are positive constant. The angular frequency of small oscillation about the minima of the potential energy is equal to

A particle of mass m moves in a one dimensional potential energy U(x)=-ax^2+bx^4 , where a and b are positive constant. The angular frequency of small oscillation about the minima of the potential energy is equal to

For a simple harmonic oscillator, the aceeleration is 3 m//s^(2) when the displacement is 0.03 m. The angular frequency of the oscillator is

From the given figure find the frequency of oscillation of the mass m

From the given figure find the frequency of oscillation of the mass m

If at some instant of time, the displacement of a simple harmonic oscillator is 0.02 m and its acceleration is 2ms^(-2) , then the angular frequency of the oscillator is

A block of mass m connected with a smooth prismatic wedge of mass M is released from rest when the spring is relaxed. Find the angular frequency of oscillation.