If `alpha,beta,gamma,delta` are the four solutions of the equation `tan(theta+pi/4)=3 tan 3theta.` No two of which have equal tangents, then the value of `tan alpha+tan beta+tan gamma+tan delta=`

Options

A. `-1//3`
B. `-2`
C. 0
D. none of these

Answer

A

Explanation

We have `tan( theta + (pi)/(4))= 3tan 3 theta `
or `(1+ tan theta)/(1-tan theta) = 3 xx (3tan theta - tan^(3) theta)/(1-3tan^(2) theta)`
`rArr (1+t)/(1-t) = 3 ((3t-t^(3))/(1-3t^(2)))" "` (putting `t = tan theta`)
`or 3t^(4) - 6t^(2) + 8t- 1 =0`
Hence,
`S_1 `= sum of roots `=t_1 + t_2 + t_3 + t_4 =0`
`S_2 ` = sum of product of roots taken two at a time = -2
`S_3` = sum of product of roots taken three at time `= -8//3`
`S_4` = product of all roots `=-1//3`
`(1)/(t_1) + (1)/(t_2) + (1)/(t_3) + (1)/(t_4) = (sum t_1 t_2 t_3)/(t_2t_2t_3t_4) = (-8//3)/(-1//3) =8`