Solve `sin^(2) theta gt cos^(2) theta`.

Answer

`n pi+pi/4 lt theta lt n pi + (3pi)/4, n in Z`

Explanation

`sin^(2) theta gt cos^(2) theta`
`rArr cos 2 theta lt 0`
`rArr (pi//2) lt 2 theta lt (3pi //2)`
or `(pi//4) lt theta lt (3pi//4)`
Taking general values, i.e., adding `2 n pi`, we get
`2npi+pi//2 lt 2 theta lt 2 n pi +3 pi//2, n in Z`
or `n pi + pi//4 lt theta lt n pi +3 pi//4`