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If cos alpha+cos beta=0=sin alpha+sinbet...

If `cos alpha+cos beta=0=sin alpha+sinbeta, then cos2alpha+cos 2beta=`

A

`-2sin(alpha+beta)`

B

`-2cos(alpha+beta)`

C

`2sin(alpha+beta)`

D

`2cos(alpha+beta)`

Text Solution

Verified by Experts

The correct Answer is:
C
`cos alpha + cos beta = 0 = sin alpha + sin beta`
Squaring and adding, we get
`2+2 cos (alpha-beta)=0`
`therefore cos (alpha - beta)=-1`
`therefore cos 2alpha + cos 2beta`
`=2 cos (alpha+beta)cos (alpha-beta)`
`=-2 cos (alpha+beta)`
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