Home
Class 12
MATHS
The number of real solution of equation ...

The number of real solution of equation `tan^(-1)x+cot^(-1)(-|x|)=2tan^(-1)(6x)` is

A

4

B

3

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
When x lt 0, wwe have `tan^(-1)(6x)=(pi)/(4)`
`rArr x =(1)/(6)`, which is not possible
When `x ge 0`, we have `(pi)/(4)=tan^(-1)(6x)-tan^(-1)(x)`
`rArr (6x-x)/(1+6x^(2))=1`
`rArr x=(1)/(2),(1)/(3)`
Promotional Banner

Similar Questions

Explore conceptually related problems

cot(tan^(-1)x+cot^(-1)x)

Solve tan^(-1) x + cot^(-1) (-|x|) = 2 tan^(-1) 6x

The number of solutions of equation 2 tan^(-1)(x + 1) = cos^(-1)(x/2) .

The number of solutions of the equation tan^(-1)(1+x)+tan^(-1)(1-x)=(pi)/(2) is 2(b)3 (c) 1(d)0

The number of solutions of the equation tan^(-1)(x+1)+tan^(-1)x+tan^(-1)(x-1)=tan^(-1)3

A solution of the equation tan^(-1)(1+x)+tan^(-1)(1-x)=(pi)/(2) is

The general solution of equation tan x.tan4x=1