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ABCD a parallelogram, and A1 and B1 are ...

ABCD a parallelogram, and `A_1 and B_1` are the midpoints of sides BC and CD, respectively. If `vec(aA)_1` `+ vec(AB)_1 = lamda vec(AC)`, then `lamda` is equal to `

A

`(1)/(2)`

B

`1`

C

`(3)/(2)`

D

`2 `

Text Solution

Verified by Experts

The correct Answer is:
C


Ler P.V. of A, B and D be `vec0, vecb and vecd`, respectively.
Then P.V. of C, `vecc=vecb+ vecd`
Also P.V of `A_1= vecb+ (vecd)/(2) `
and P.V of `B_1 = vecd + (vecb)/(2)`
`rArr vec(AA)_1 + vec(AB)_1 = (3)/(2) (vecb + vecd) = (3)/(2) vec(AC)`
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