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In a trapezium ABCD the vector B vec C ...

In a trapezium ABCD the vector `B vec C = lambda vec(AD).` If `vec p = A vec C + vec(BD)` is coillinear with `vec(AD)` such that `vec p = mu vec (AD),` then

A

`mu= alpha +2`

B

`mu+ alpha =1`

C

`alpha = mu +1`

D

`mu =alpha +1`

Text Solution

Verified by Experts

The correct Answer is:
D
`vecc - vec b = alpha vecd and vecp = vec(AC) + vec(BD) = mu vec(AD)`

Hence, `vecp = vecc + vecd - vecb = mu vecd` (using `vecc - vecb = alpha vecd`)
or `alpha + 1 = mu`
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