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If points hati+hatj, hati -hatj and p ha...

If points `hati+hatj, hati -hatj and p hati +qhatj+rhatk` are collinear, then

A

`p=1`

B

`r=0`

C

`q in R`

D

`q ne 1`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
Points `A(hati + hatj), B(hati -hatj) and C(phati +qhatj + rhatk)` are collinear
Now `vec(AB) = -2hatj and vec(BC) = (p-1)hati + (q-1)hatj + rhatk`
Vectors `vec(AB) and vec(BC)` must be collinear
`rArr p=1, r =0 and q ne 1`
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