Home
Class 12
MATHS
ABCD is a parallelogram. L is a point on...

ABCD is a parallelogram. L is a point on BC which divides BC in the ratio `1:2`. AL intersects BD at P.M is a point on DC which divides DC in the ratio `1 : 2` and AM intersects BD in Q.
Point P divides AL in the ratio

A

`1:2`

B

`1:3`

C

`3:1`

D

`2:1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break down the information given and apply the properties of parallelograms and similar triangles. ### Step 1: Understand the Geometry We have a parallelogram ABCD with points L and M dividing sides BC and DC in the ratios 1:2 respectively. This means: - \( BL : LC = 1 : 2 \) - \( DM : MC = 1 : 2 \) ### Step 2: Set Up Coordinates Assume the coordinates of the points: - \( A(0, 0) \) - \( B(a, 0) \) - \( C(a + b, c) \) - \( D(b, c) \) From this, we can find the coordinates of points L and M: - Point L divides BC in the ratio 1:2, so using the section formula: \[ L = \left( \frac{2a + (a + b)}{3}, \frac{2 \cdot 0 + c}{3} \right) = \left( \frac{3a + b}{3}, \frac{c}{3} \right) \] - Point M divides DC in the ratio 1:2, so: \[ M = \left( \frac{2b + (a + b)}{3}, \frac{2c + c}{3} \right) = \left( \frac{a + 3b}{3}, \frac{3c}{3} \right) = \left( \frac{a + 3b}{3}, c \right) \] ### Step 3: Find Intersection Points Next, we need to find the intersection points P and Q: - The line AL can be represented by the equation derived from points A and L. - The line AM can be represented by the equation derived from points A and M. - The line BD can be represented by the equation derived from points B and D. ### Step 4: Use Similar Triangles Since triangles APD and LPB are formed, we can use the property of similar triangles: - By the properties of similar triangles: \[ \frac{AP}{LP} = \frac{AD}{BL} \] ### Step 5: Calculate Ratios From the ratios given: - \( BL : LC = 1 : 2 \) implies \( BL = \frac{1}{3} BC \) and \( LC = \frac{2}{3} BC \). - Therefore, \( AD = BC \) (since opposite sides of a parallelogram are equal). Substituting these values into the ratio: \[ \frac{AP}{LP} = \frac{BC}{BL} = \frac{BC}{\frac{1}{3}BC} = 3 \] ### Step 6: Final Ratio Thus, we can conclude that: \[ AP : LP = 3 : 1 \] ### Conclusion The point P divides AL in the ratio \( 3 : 1 \).

To solve the problem step by step, let's break down the information given and apply the properties of parallelograms and similar triangles. ### Step 1: Understand the Geometry We have a parallelogram ABCD with points L and M dividing sides BC and DC in the ratios 1:2 respectively. This means: - \( BL : LC = 1 : 2 \) - \( DM : MC = 1 : 2 \) ### Step 2: Set Up Coordinates ...
Promotional Banner

Topper's Solved these Questions

  • INTRODUCTION TO VECTORS

    CENGAGE|Exercise MATRIX-MATCH TYPE|3 Videos
  • INTRODUCTION TO VECTORS

    CENGAGE|Exercise Exercise (Numerical)|6 Videos
  • INTRODUCTION TO VECTORS

    CENGAGE|Exercise LINKED COMPREHENSION TYPE|2 Videos
  • INTEGRALS

    CENGAGE|Exercise Solved Examples And Exercises|324 Videos
  • INVERSE TRIGONOMETRIC FUNCTIONS

    CENGAGE|Exercise Question Bank|24 Videos

Similar Questions

Explore conceptually related problems

ABCD is a parallelogram. L is a point on BC which divides BC in the ratio 1:2 . AL intersects BD at P.M is a point on DC which divides DC in the ratio 1 : 2 and AM intersects BD in Q. Point Q divides DB in the ratio

ABCD is a parallelogram. L is a point on BC which divides BC in the ratio 1:2 . AL intersects BD at P.M is a point on DC which divides DC in the ratio 1 : 2 and AM intersects BD in Q. PQ : DB is equal to

ABCD is a parallelogram and E is a point, on BC. If the diagonal BD intersects AE at F, prove that AFxxFBxxEFxxFD .

Let ABC be a triangle.If P is a point such that AP divides BC in the ratio 2:3,BP divides CA in the ratio 3:5 then the ratio in which CP divides AB is

In DeltaABC , P is the mid point of BC,Q divides CA internally in the ratio 2:1 and R divides AB externally in the ratio 1:2 then

ABCD is a parallelogram.L and M are points on AB and DC respectively and AL=CM. prove that LM and BD bisect each other.

In the given figure, ABCD is a parallelogram. AE divides the line segment BD in the ratio 1 : 2. If BE = 1.5 cm find BC.

ABCD is parallelogram.If L and M are the middle points of BC and CD, then bar(AL)+bar(AM) equals