Home
Class 12
MATHS
Let A, B, C, D, E represent vertices of ...

Let A, B, C, D, E represent vertices of a regular pentagon ABCDE. Given the position vector of these vertices be `veca, veca + vecb, vecb, lamda veca and lamda vecb`, respectively.
AD divides EC in the ratio

A

`cos""(2pi)/(5) : 1`

B

`cos""(3pi)/(5) : 1`

C

`1 : 2 cos""(pi)/(5)`

D

`1 : 2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio in which line segment AD divides line segment EC in a regular pentagon ABCDE, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Pentagon Structure**: - A regular pentagon has equal sides and equal angles. The vertices are labeled as A, B, C, D, and E. 2. **Identify the Position Vectors**: - The position vectors of the vertices are given as follows: - \( \vec{A} = \vec{a} \) - \( \vec{B} = \vec{a} + \vec{b} \) - \( \vec{C} = \vec{b} \) - \( \vec{D} = \lambda \vec{a} \) - \( \vec{E} = \lambda \vec{b} \) 3. **Visualize the Problem**: - Draw the pentagon and label the vertices A, B, C, D, and E. Draw the diagonals AD and EC. 4. **Use the Properties of the Pentagon**: - In a regular pentagon, the diagonals intersect at specific angles. The angles between the diagonals can be used to find the ratios of the segments. 5. **Apply the Law of Sines**: - In triangle OAB (formed by the origin O and points A and B), we can use the Law of Sines to find the lengths of the segments. - Let \( O \) be the center of the pentagon. The angles at O can be calculated based on the regular pentagon's properties. 6. **Calculate the Lengths**: - Assign lengths to the sides of the triangle based on the properties of the pentagon. For instance, let \( OC = CD = 1 \) (for simplicity). - Using the Law of Sines: \[ \frac{OD}{\sin(\text{angle opposite to } OD)} = \frac{OC}{\sin(\text{angle opposite to } OC)} \] 7. **Determine the Ratio**: - From the calculations, we find the lengths of segments OD and OC. - The ratio \( \frac{AD}{EC} \) can then be expressed in terms of the lengths found. 8. **Final Calculation**: - Substitute the values obtained from the Law of Sines into the ratio to find the exact ratio in which AD divides EC. 9. **Conclusion**: - The final answer will be in the form of \( \frac{1}{2 \cos(\frac{5\pi}{5})} \).

To solve the problem of finding the ratio in which line segment AD divides line segment EC in a regular pentagon ABCDE, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Pentagon Structure**: - A regular pentagon has equal sides and equal angles. The vertices are labeled as A, B, C, D, and E. 2. **Identify the Position Vectors**: ...
Promotional Banner

Topper's Solved these Questions

  • INTRODUCTION TO VECTORS

    CENGAGE|Exercise MATRIX-MATCH TYPE|3 Videos
  • INTRODUCTION TO VECTORS

    CENGAGE|Exercise Exercise (Numerical)|6 Videos
  • INTRODUCTION TO VECTORS

    CENGAGE|Exercise LINKED COMPREHENSION TYPE|2 Videos
  • INTEGRALS

    CENGAGE|Exercise Solved Examples And Exercises|324 Videos
  • INVERSE TRIGONOMETRIC FUNCTIONS

    CENGAGE|Exercise Question Bank|24 Videos

Similar Questions

Explore conceptually related problems

Let A,B,C,D,E represent vertices of a regular pentangon ABCDE. Given the position vector of these vertices be a,a+b,b, lamda a and lamdab respectively. Q. AD divides EC in the ratio

The position vectors of A,B,C,D are veca,b,2vec+3vecb and veca-2vecb respectively show that vec(DB)=3vecb - veca and vec(AC)=veca+3vecb .

If [veca xx vecb vecb xx vec c vec c xx vec a] = lamda [veca vecb vec c ]^2 then lamda is equal to

The points with position vectors veca + vecb, veca-vecb and veca +k vecb are collinear for all real values of k.

A, B, C and D have position vectors veca, vecb, vecc and vecd , repectively, such that veca-vecb = 2(vecd-vecc) . Then

Vectors vecA and vecB satisfying the vector equation vecA+ vecB = veca, vecA xx vecB =vecb and vecA.veca=1 . Vectors and vecb are given vectosrs, are

Vectors vecA and vecB satisfying the vector equation vecA+ vecB = veca, vecA xx vecB =vecb and vecA.veca=1 . Vectors and vecb are given vectosrs, are

given that veca. vecb = veca.vecc, veca xx vecb= veca xx vecc and veca is not a zero vector. Show that vecb=vecc .

given that veca. vecb = veca.vecc, veca xx vecb= veca xx vecc and veca is not a zero vector. Show that vecb=vecc .