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If veca +vecb +vecc=0, |veca|=3,|vecb|=5...

If `veca +vecb +vecc=0, |veca|=3,|vecb|=5, |vecc|=7` , then find the angle between `veca and vecb`.

A

`pi/2`

B

`pi/3`

C

`pi/4`

D

`pi/6`

Text Solution

Verified by Experts

The correct Answer is:
B

Let `theta` be the angle between `veca` and `vecb`
Then `angleC=pi-theta`
`therefore cos(pi-theta) = (3^(2)+5^(2)-7^(2))/(2(3)(5))`
`therefore -costheta=-1/2`
`therefore theta=60^(@)`
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CENGAGE-VECTORS; DEFINITION, GEOMETRY RELATED TO VECTORS-DPP 1.1
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