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veca=2hati+hatj+2hatk, vecb=hati-hatj+ha...

`veca=2hati+hatj+2hatk, vecb=hati-hatj+hatk` and non zero vector `vecc` are such that `(veca xx vecb) xx vecc = veca xx (vecb xx vecc)`.
Then vector `vecc` may be given as

A

`4hati+2hatj+4hatk`

B

`4hati-2hatj+4hatk`

C

`hati+hatj+hatk`

D

`hati-4hatj+hatk`

Text Solution

Verified by Experts

The correct Answer is:
A
`(veca xx vecb) xx vecc = veca xx (vecb xx vecc)`
`rArr (veca.vecc)vecb-(vecb.vecc)veca`
`=(veca.vecc)vecc-(veca.vecb)vecc`
`rArr veca` and `vecc` are parallel.
`therefore vecc` may be equal to `4hat(i)+2hatj+4hatk`
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