Home
Class 12
MATHS
A=[{:(l(1),m(1),n(1)),(l(2),m(2),n(2)),(...

`A=[{:(l_(1),m_(1),n_(1)),(l_(2),m_(2),n_(2)),(l_(3),m_(3),n_(3)):}]` and `B=[{:(p_(1),q_(1),r_(1)),(p_(2),q_(2),r_(2)),(p_(3),q_(3),r_(3)):}]`
Where `p_(i), q_(i),r_(i)` are the co-factors of the elements `l_(i), m_(i), n_(i)` for `i=1,2,3`. If `(l_(1),m_(1),n_(1)),(l_(2),m_(2),n_(2))` and `(l_(3),m_(3),n_(3))` are the direction cosines of three mutually perpendicular lines then `(p_(1),q_(1), r_(1)),(p_(2),q_(2),r_(2))` and `(p_(3),q_(),r_(3))` are

A

the direction cosines of three mutually perpendicular lines

B

the direction ratios of three mutually perpendicular lines which are not direction cosines.

C

the direction cosines of three lines which need not be perpendicular

D

the direction of three lines which need not be perpendicular

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to establish the relationship between matrices A and B, given that the direction cosines in A represent three mutually perpendicular lines. ### Step-by-step Solution: 1. **Define the Vectors**: Let the vectors corresponding to the direction cosines be defined as: \[ \vec{A} = l_1 \hat{i} + m_1 \hat{j} + n_1 \hat{k} \] \[ \vec{B} = l_2 \hat{i} + m_2 \hat{j} + n_2 \hat{k} \] \[ \vec{C} = l_3 \hat{i} + m_3 \hat{j} + n_3 \hat{k} \] 2. **Understanding Co-factors**: The co-factors of the elements in A are given as: \[ p_1 = m_2 n_3 - m_3 n_2, \quad q_1 = n_2 l_3 - n_3 l_2, \quad r_1 = l_2 m_3 - l_3 m_2 \] Similarly for \( p_2, q_2, r_2 \) and \( p_3, q_3, r_3 \). 3. **Condition of Perpendicularity**: Since the direction cosines are mutually perpendicular, the scalar triple product of the vectors must be zero: \[ \vec{A} \cdot (\vec{B} \times \vec{C}) = 0 \] This leads us to the determinant condition: \[ \begin{vmatrix} l_1 & m_1 & n_1 \\ l_2 & m_2 & n_2 \\ l_3 & m_3 & n_3 \end{vmatrix} = 0 \] 4. **Calculate the Determinant**: Expanding the determinant, we have: \[ l_1 (m_2 n_3 - m_3 n_2) - m_1 (l_2 n_3 - l_3 n_2) + n_1 (l_2 m_3 - l_3 m_2) = 0 \] This implies that the vectors are linearly dependent. 5. **Relate Co-factors to Direction Cosines**: The co-factors \( (p_1, q_1, r_1), (p_2, q_2, r_2), (p_3, q_3, r_3) \) can be interpreted as the direction cosines of the lines perpendicular to the original lines represented by A. Thus, we can conclude that: \[ \vec{B} = k_1 \cdot \vec{A}, \quad \vec{C} = k_2 \cdot \vec{A} \] for some scalars \( k_1 \) and \( k_2 \). 6. **Final Conclusion**: Therefore, the vectors \( (p_1, q_1, r_1), (p_2, q_2, r_2), (p_3, q_3, r_3) \) represent the direction cosines of the lines perpendicular to the lines represented by \( (l_1, m_1, n_1), (l_2, m_2, n_2), (l_3, m_3, n_3) \).

To solve the problem, we need to establish the relationship between matrices A and B, given that the direction cosines in A represent three mutually perpendicular lines. ### Step-by-step Solution: 1. **Define the Vectors**: Let the vectors corresponding to the direction cosines be defined as: \[ \vec{A} = l_1 \hat{i} + m_1 \hat{j} + n_1 \hat{k} ...
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    CENGAGE|Exercise Solved Examples And Exercises|246 Videos

Similar Questions

Explore conceptually related problems

If l_(1), m_(1), n_(1), l_(2), m_(2), n_(2) and l_(3), m_(3), n_(3) are direction cosines of three mutuallyy perpendicular lines then, the value of |(l_(1),m_(1),n_(1)),(l_(2),m_(2),n_(2)),(l_(3),m_(3),n_(3))| is

Let l_(i),m_(i),n_(i);i=1,2,3 be the direction cosines of three mutually perpendicular vectors in space.Show that AA=I_(3) where A=[[l_(2),m_(2),n_(2)l_(3),m_(3),n_(3)]]

The direction cosines of a line equally inclined to three mutually perpendiclar lines having direction cosines as l_(1),m_(1),n_(1),l_(2),m_(2),n_(2) and l_(3), m_(3),n_(3) are

Let l_(1),m_(1),n_(1);l_(2),m_(2),n_(2) and l_(3),m_(3),n_(3) be the direction cosines of three mutually perpendicular lines.Show that the direction ratios of the line which makes equal angles with each of them are (l_(1)+l_(2)+l_(3)),(m_(1)+m_(2)+m_(3)),(n_(1)+n_(2)+n_(3))

If the direction cosines of two lines are l_(1), m_(1), n_(1) and l_(2), m_(2), n_(2) , then find the direction cosine of a line perpendicular to these lines.

If l_(1), m_(1), n_(1) and l_(2), m_(2), n_(2) are the direction cosines of two lines and l , m, n are the direction cosines of a line perpendicular to the given two lines, then

If l_(i)^(2)+m_(i)^(2)+n_(i)^(2)=1 , (i=1,2,3) and l_(i)l_(j)+m_(i)m_(j)+n_(i)n_(j)=0,(i ne j,i,j=1,2,3) and Delta=|{:(l_(1),m_(1),n_(1)),(l_(2),m_(2),n_(2)),(l_(3),m_(3),n_(3)):}| then

If three mutually perpendicular lines have direction cosines (l_(1),m_(1),n_(1)),(l_(2),m_(2),n_(2)) and (L_(3),m_(3),n_(3)) then the line having direction cosines l_(1)+l_(2)+l_(3),m_(1)+m_(2)+m_(3), and n_(1)+n_(2)+n_(3) ,make an angle of