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A and B are two points with coordinates ...

A and B are two points with coordinates `(x_(1),y_(1),z_(1))` and `(x_(2),y_(2),z_(2))`, respectively, in space. Let P and Q be feet of the perpendicular drawn from A and B to a line L whose direction ratios are l,m,n. Let `theta` be the angle between AB and L then find the value of `cos theta`

A

`PQ=Abcostheta`

B

`PQ=|(x_(2)-x_(1))l+(y_(2)-y_(1))m+(z_(2)-z_(1))n|`

C

`PQ=(|(x_(2)-x_(1))l+(y_(2)-y_(1))m+(z_(2)-z_(1))n|)/(sqrt(l^(2)+m^(2)+n^(2))`

D

AB and PQ are always coplanar.

Text Solution

Verified by Experts

The correct Answer is:
A, C

DC's of AB are `(x_(2)-x_(1))/(AB), (y_(2)-y_(1))/(AB), (z_(2)-z_(1))/(AB)`
DC's of L are
`l/sqrt(l^(2)+m^(2)+n^(2)), m/sqrt(l^(2)+m^(2)+n^(2)),n/sqrt(l^(2)+m^(2)+n^(2))`
`costheta=(((x_(2)-x_(1))l+(y_(2)-y_(1))m+(z_(2)-z_(1))n)/sqrt(l^(2)+m^(2)+n^(2)))`
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