`A(1,-1,-3), B(2, 1,-2) & C(-5, 2,-6)` are the position vectors of the vertices of a triangle ABC. The length of the bisector of its internal angle at A is :

Let A (4, 7, 8), B (2, 3, 4) and C (2, 5, 7) be the position vectors of the vertices of a triangle ABC. The length of the internal bisector of the angle at A is

Let A(4,7,8)B(2,3,4) and C(2,5,7) be the position vectors of the vertices of a triangle ABC.Then the length of the internal angular bisector of angle A is

If A(1, -1, -3), B(2, 1, -2), C(-5, 2, -6) are the vertices of a DeltaABC , then the length of internal bisector of angle A is

The vertices of a triangle are A(-1,-7),B(5,1) and C(1,4). The equation of the bisector of the angle ABC

If A(3, 5, -4), B(-1, 1, 2) and C(-5, -5, -2) are the vertices of Delta ABC, then the triangle is

If A(1, 4, 2), B(-2, 1, 2) and C(2, -3, 4) are the vertices of the triangle ABC, then find the angles of the triangle ABC.

A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the angle bisector of angleABC is x+y =2 Equation of side AB is

If A (-1, 4,2), B(3, -2, 0) and C(1,2,4) are the vertices of the triangle ABC, then the length of its median through the vertex A is-