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The resistance and conductivity of 0.02 ...

The resistance and conductivity of `0.02 M KCl` solution are `82.4 ohm` and `0.002768 S ch^(-1)` respectively . When filled with `0.005 N K_(2)SO_(4)`, the solution had a resistance of `324ohm`. Calculate `:`
`a.` Cell constant
`b.` Conductance of `K_(2)SO_(4)` solution
`c.` Conductivity of `K_(2)SO_(4)` solution
`d.` Equivalent conductivity of `K_(2)SO_(4)` solution
`e.` Molar conductivity of `K_(20SO_(4)` solution.

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The resistance and conductivity of 0.02 M KCl solution are 82.4 ohm and 0.002768 S cm^(-1) respectively . When filled with 0.005 N K_(2)SO_(4) , the solution had a resistance of 324ohm . Calculate : a. Cell constant b. Conductance of K_(2)SO_(4) solution c. Conductivity of K_(2)SO_(4) solution d. Equivalent conductivity of K_(2)SO_(4) solution e. Molar conductivity of K_(2)SO_(4) solution.

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