A gram molecule of a gas at `127^(@)C` expands isothermally until its volume is doubled. Find the amount of work done and heat absorbed.

A gram molecule of gas at 27^(@)C expands isothermally untill its volume is doubled. Find the amount of work done and heat absorbed. Take R=8.31J mol e^(-1) K^(-1) .

A gm molecule of a perfect gas at 100^@C expands isothermally until its volume is doubled. Find the amount of work done and the heat absorbed. R = 8.3J//gm-mol//K .

One gram mole of oxygen gas at 127^@C expands isothermally until its volume is doubled. Find the amount of work done and heat produced R=8.314"jmole"^-1k^-1

Three moles of an ideal gas at 127^(@)C expands isothermally untill the volume is doubled. Calculate the amount of work done and heat absorbed.

A gram mole of a gas at 27^@C expands isothermally until its volume is doubled. Calculate the amount of work done. (R=8 J mol^(-1) K^(-1))

A volume of gas at 15^(@)C expands adiabatically until its volume is doubled. Find the resultant temperture given that the ratio of specific heat capacity of the gas =1.4 .

The volume of 1 mol of a gas is doubled when it expands isothermally at 127^(@)C . Find out the amount of work done and heat absorbed.

If x mole of ideal gas at 27^(@)C expands isothermally and reversibly from a volume of y to 10 y, then the work done is

If x mole of ideal gas at 27^(@)C expands isothermally and reversibly from a volume of y to 10 y, then the work done is