The displacement of a body executing `SHM` is given by `x=A sin (2pi+pi//3)`. The firs time from `t=0` when the velocity is maximum is

The displacement of a body executing SHM is given by x=A sin (2pit+pi//3) . The firs time from t=0 when the velocity is maximum is

The displacement of a body executing SHM is given by x=A sin (2pi t+pi//3) . The first time from t=0 when the velocity is maximum is

The displacement of a body executing SHM is given by x=Asin(2pit+pi//6) . The first time from t = 0 when the velocity is maximum is :

The displacement of a body executing SHM is given by x=lambdasin(2pit+pi//3) . The first time from t = 0 when the velocity is maximum is :

The displacement of a particle executing S.H.M is given by x= 0.01 sin 100pi (t + 0.05) . The time period is

The displacement of a particle executing SHM is given by y=0.5 sin100t cm . The maximum speed of the particle is

The displacement of a particl executing SHM is given by Y=10 sin (3t+pi//3)m and t is in seconds. The initial displacement and maximum velocity of the particle are respectively

The displacement of a particle executing SHM is given by. y=5 sin(4t+pi/3) If T is the time period and the mass of the particle is 2 g, the kinetic energy of the particle when t=T/4 is given by,

If the displacement of a particle executing SHM is given by y=0.30 sin (220t +0.64) in metre , then the frequency and maximum velocity of the particle is