A line passes through the point `A(hat i+2hat j+3hat k)` and is parallel to the vector `vecV = (hat i+hat j-hat k)` The shortest distance from the origin, of the line is (A) `sqrt2` (B) `sqrt4` (C) `sqrt5` (D) `sqrt6`

A line passes through the point A(5,-2.4) and it is parallel to the vector (2hat(i) -hat(j) +3hat(k)) .The vector equations of the line is

A line passes through the points whose pdotvdot are hat i+ hat j-2 hat k and hat i-3 hat j+ hat k .The position vector of a point on it at unit distance from the first point is

Find the vector equation of a line passing through a point with position vector 2hat i-hat j+hat k ,and parallel to the line joining the points -hat i+4hat j+hat k and hat i+2hat j+2hat k. Also, find the cartesian equivalent of this equation.

If theta is the angle between the vectors 2 hat i-2 hat j+4 hat k\ a n d\ 3 hat i+ hat j+2 hat k , then sintheta= 2/3 b. 2/(sqrt(7)) c. (sqrt(2))/7 d. sqrt(2/7)

If theta is the angle between the vectors 2 hat i-2 hat j+4 hat k\ a n d\ 3 hat i+ hat j+2 hat k , then sintheta= 2/3 b. 2/(sqrt(7)) c. (sqrt(2))/7 d. sqrt(2/7)