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The straight line 2x-3y = 1 divides the ...

The straight line 2x-3y = 1 divides the circular region `x^2+ y^2 le6` into two parts. If S = { `( 2 , 3/4) , (5/2,3/4) , (1/4,-1/4), (1/8,1/4)`}, then the number of point(s) in S lying inside the smaller part is

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`x^2+y^2<=6`
`L:2x-3y-1=0`
`L(0,0)=0-0-1<0`
`2h-3k-1<0`
`(2,3/4)`
` S:4+9/16-6<0`
`L:2*2-3*3/4-1>0`
`(5/2,3/4)`
...
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