For the reaction
`2AB(g)hArrA_(2)(g)+B_(2)(g)`
The degree of dissociation `(alpha)` of `HI(g)` is related to equilibrium constant `K_(p)` by the expression

For the reaction 2HI(g)hArrH_(2)(g)+I_(2)(g)+I_(2)(g) The degree of dissociation (alpha) of HI(g) is related to equilibrium constant K_(p) by the expression a. (1+2sqrt(K_(p)))/2 , b. sqrt((1+2K_(p))/2) c. sqrt((2K_(p))/(1+2K_(p))) , d. (2sqrt(K_(p)))/(1+2sqrt(K_(p)))

For the reaction 2HI(g)hArrH_(2)(g)+I_(2)(g) The degree of dissociation (alpha) of HI(g) is related to equilibrium constant K_(p) by the expression a. (1+2sqrt(K_(p)))/2 , b. sqrt((1+2K_(p))/2) c. sqrt((2K_(p))/(1+2K_(p))) , d. (2sqrt(K_(p)))/(1+2sqrt(K_(p)))

For the reaction, 2HI(g) iff H_2(g) +I_2 (g) the degree of dissociation ( alpha ) of HI (g) is related to the equilibrium constant, K_p by expression

For the reaction PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) , the equation connecting the degree of dissociation (alpha) of PCl_(5)(g) with the equilibrium constant K_(p) is

For the reaction PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) , the equation connecting the degree of dissociation (alpha) of PCl_(5)(g) with the equilibrium constant K_(p) is

For the reaction N_(2)O_(4)(g)hArr2NO_(2)(g) , the degree of dissociation at equilibrium is 0.2 at 1 atm pressure. The equilibrium constant K_(p) will be

For the reaction N_(2)O_(4)(g)hArr2NO_(2)(g) , the degree of dissociation at equilibrium is 0.2 at 1 atm pressure. The equilibrium constant K_(p) will be

At temperature T, a compound AB_2(g) dissociation according to the reaction, 2AB _2(g) hArr 2AB(g) +B_2(g) with degree of dissociation, alpha , which is small compared to unity . Deduce the expression for alpha in terms of the equilibrium constant K_p and the total pressure P.