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The perpendicular from the origin to the line `y = m x + c` meets it at the point `(-1, 2)`. Find the values of m and c.

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The given equation of the line is `y = mx + c.`
From the given condition, the perpendicular from the origin meets the given line at `(-1, 2).`
Hence, the line joining the points `(0, 0)` and `(-1, 2)` is perpendicular to the given line.
The slope of the line joining `(0, 0)` and `(-1, 2)` is
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NCERT-STRAIGHT LINES-EXERCISE 10.3
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  5. Find the coordinates of the foot of perpendicular from the point (1, 3...

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  6. The perpendicular from the origin to the line y = m x + c meets it...

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  7. If p and q are the lengths of perpendiculars from the origin to the l...

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  8. In the triangle ABC with vertices A (2, 3), B (4, –1) and C (1, 2), f...

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  9. If p is the length of perpendicular from the origin to the line whose...

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  14. Find the distance between parallel lines (i) 15 x + 8y 34 = 0and 15 ...

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  17. Find angles between the lines sqrt(3)x+y=1and x+sqrt(3)y=1.

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