Find t values of the parameter `a` such that the rots `alpha,beta` of the equation `2x^2+6x+a=0` satisfy the inequality `alpha//beta+beta//alpha<2.`

Explanation

We have `alpha + beta = -3 and alpha beta = a//2, Now`,
` (alpha )/(beta) + (beta)/(aplha) lt 2`
or `(alpha ^(2) + beta^(2))/(alpha beta)lt 2`
or `(alpha ^(2) + beta^(2) - 2alpha beta)/(alpha beta)lt 2`
`rArr (9 - a)/(a//2) lt 2`
or `(9 - a)/(a) - 1 lt 0`
or `(9- 2a)/(a) lt 0`
or (2a -9)/(a) gt 0`
`rArr a lt 0 or a gr 9//2`