The Fobonacci sequence is defined by `1=a_1=a_2a n da_n=a_(n-1)+a_(n-2,)n > 2.` Find `(a_(n+1))/(a_n),forn=5.`

Explanation

`1=a_(1)=a_(2)`
`a_(n)=a_(n-1)+a_(n-2),ngt2`
`thereforea_(3)=a_(2)+a_(1)=1+1=2`
`a_(4)=a_(3)+a_(2)=2+1=3`
`a_(5)=a_(4)+a_(3)=3+2=5`
`a_(6)=a_(5)+a_(4)=5+3=8`
`therefore` For n=5, `(a_(n+1))/(a_(n))=(a_(6))/(a_(5))=8/5`