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Let `a in (0,1)` satisfies the equation `a^(2008)-2a+1=0v a l u e s(s)toS` is `2010` b. `2009` c. `2008` d. `2`

A

2010

B

2009

C

2008

D

2

Text Solution

Verified by Experts

The correct Answer is:
A

Let a=1,then `S_(1)=2008`
If `ane1` tehn `S=(a^(2008)-1)/(a-1)`
But `a^(2008)=2a-1,` therefore,
`S_(2)=(2(a-1))/(a-1)=2`
`thereforeS=S_(1)+S_(2)=2010`
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