If `a ,b ,a n dc` are in A.P. `p ,q ,a n dr` are in H.P., and `a p ,b q ,a n dc r` are in G.P., then `p/r+r/p` is equal to `a/c-c/a` b. `a/c+c/a` c. `b/q+q/b` d. `b/q-q/b`

Options

A. A.P
B. G.P
C. G.P
D. none of these

Answer

D

Explanation

a,b, and c are in A.P. Hence,
2b=a+c
`a/(bc)+2/b=(a+2c)/(bc)ne2/c`
`rArra/(bc),1/c,2/b` are not in A.P.
`(bc)/a+b/2=(2bc+ab)/(2a)nec`
Hence, the given numbers are not in H.P. Again,
`a/(bc)2/b=(2a)/(b^(2)c)ne1/c^(2)`
Therefore, the given numbers are not in G.P.